Answer
$38$
Work Step by Step
Since, we have from the graph:
$\sum_{i=1}^{5}(b_i^2-1)=((4)^2-1)+((2)^2-1)+((0)^2-1)+((-2)^2-1)+((-4)^2-1)$
or, $=15+3-1+3+15$
or, $=38$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 50
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