Answer
$\sum_{i=1}^{n}(\dfrac{4^i}{i})$
Work Step by Step
Since, we have $4+\dfrac{4^2}{2}+\dfrac{4^3}{3}+.......+\dfrac{4^n}{n}$
This can be summed up with the summation notation as:
$\sum_{i=1}^{n}(\dfrac{4^i}{i})$
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