Answer
$0$
Work Step by Step
Since, we have from the graph:
$\sum_{i=1}^{5}(2a_i+b_i)=[2(-4)+4]+[2(-2)+2]+[2(0)+0]+[2(2)+(-2)]+[2(4)+(-4)]$
or, $=-4-2+0+2+4$
or, $=0$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 51
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