Answer
$225$
Work Step by Step
Since, we have
$\sum_{i=1}^{5}(i^3)=(1^3+2^3+3^3+4^3+5^3)$
or, $=1+8+27+64+125$
Hence, we get
$=225$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 20
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