Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - Test: Chapter 12 - Page 845: 9

Answer

$\dfrac{1}{2}$

Work Step by Step

Using the properties of logarithms, the given expression, $ \log_{100} 10 ,$ is equivalent to \begin{align*} & \log_{100} 10 \\&= \log_{100} \sqrt{100} \\&= \log_{100} 100^{1/2} \\\\&= \dfrac{1}{2}\log_{100} 100 &(\text{use }\log_b x^y=y\log_bx) \\\\&= \dfrac{1}{2}(1) &(\text{use }\log_b b=1) \\\\&= \dfrac{1}{2} .\end{align*}Hence, $\log_{100} 10$ simplifies to $\dfrac{1}{2}$.
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