Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - Test: Chapter 12 - Page 845: 13

Answer

$2^m=\dfrac{1}{2}$

Work Step by Step

Since $\log_b y=x$ implies $y=b^x,$ then the given equation, $ m=\log_2\dfrac{1}{2},$ is equivalent to $ 2^m=\dfrac{1}{2}$.
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