Answer
$0.477$
Work Step by Step
Using the properties of logarithms, the given expression, $
\log_a 3
,$ is equivalent to
\begin{align*}
&
\log_a \dfrac{6}{2}
\\&=
\log_a 6-\log_a 2
&(\log_b \dfrac{x}{y}=\log_b x-\log_b y)
.\end{align*}
Using the given values, $
\log_a 2=0.301
$ and $
\log_a 6=0.778
,$ the expression above becomes
\begin{align*}
&
0.778-0.301
\\&=
0.477
.\end{align*}
Hence, the given expression evaluates to $
0.477
$.
