Answer
$
5^{-4}=\dfrac{1}{625}$ is equivalent to $
\log_5\left(\dfrac{1}{625}\right)=-4$.
Work Step by Step
Since $y=b^x$ implies $\log_b y=x,$ then the given equation, $
5^{-4}=\dfrac{1}{625},$ is equivalent to $
\log_5\left(\dfrac{1}{625}\right)=-4$.