Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - Test: Chapter 12 - Page 845: 16

Answer

1.146

Work Step by Step

Using the properties of logarithms, the given expression, $ \log_a 14 ,$ is equivalent to \begin{align*} & \log_a [2(7)] \\&= \log_a 2+\log_a 7 &(\log (xy)=\log x+\log y) .\end{align*} Using the given values, $ \log_a 2=0.301 $ and $ \log_a 7=0.845 ,$ the expression above becomes \begin{align*} & 0.301+0.845 \\&= 1.146 .\end{align*} Hence, the given expression evaluates to $ 1.146 $.
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