Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - Test: Chapter 12 - Page 845: 18

Answer

$1.204$

Work Step by Step

Using the properties of logarithms, the given expression, $ \log_a 16 ,$ is equivalent to \begin{align*} & \log_a 2^4 \\&= 4(\log_a 2) &(\log x^y=y\log x) .\end{align*} Using the given value, $ \log_a 2=0.301 ,$ the expression above becomes \begin{align*} & 4(0.301) \\&= 1.204 .\end{align*} Hence, the given expression evaluates to $ 1.204 $.
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