Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 16 - Waves-I - Problems - Page 475: 55

Answer

$0.25\;m$

Work Step by Step

According the the give wave equation: $k=4\pi\; rad/m$ and $\omega=400\pi\;rad/s$ Therefore, wave velocity is given by $v=\frac{\omega}{k}=\frac{400\pi}{4\pi}\;m/s=100\;m/s$ and time period is given by $T=\frac{2\pi}{\omega}=\frac{2\pi}{400\pi}\;s=0.005\;s$ We know that the oscillating point move from maximum upward displacement to maximum downward displacement in the time interval of $\frac{T}{2}$ Therefore, in this time interval, the displacement of each wave move along the string becomes $s=v\times\frac{T}{2}$ or, $s=100\times\frac{0.005}{2}\;m$ or, $\boxed{s=0.25\;m}$
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