Answer
$\omega=523.60\;rad/s$
Work Step by Step
The equation for one of the two waves be of the form: $y(x, t)=y_m\sin(kx+\omega t)$
The other wave has the same amplitude and wavelength and travel through each other.
From the given graph, time period of each wave is
$T=2\times6\;ms=12\;ms=12\times10^{-3}\;s$
Therefore, the frequency of each wave is given by
or, $f=\frac{1}{T}$
Therefore, the angular frequency of each wave is given by
or, $\omega=2\pi f$
or, $\omega=\frac{2\pi}{T}$
or, $\omega=\frac{2\pi}{12\times10^{-3}}\;rad/s$
or, $\boxed{\omega=523.60\;rad/s}$
