Answer
$y_m = 0.50~cm$
Work Step by Step
We can write a general expression for the standing wave:
$y'(x,t) = [(2y_m) sin ~(kx)]~cos~\omega t$
The amplitude of the standing wave is $1.0~cm$
We can find $y_m$:
$2y_m = 1.0~cm$
$y_m = \frac{1.0~cm}{2}$
$y_m = 0.50~cm$
