Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 16 - Waves-I - Problems - Page 475: 53b

Answer

$$1.2 \times 10^{2} \mathrm{cm} / \mathrm{s} $$

Work Step by Step

Every traveling wave has an angular frequency of $$\omega=40 \pi \mathrm{rad} / \mathrm{s}$$ and an angular wave number of $$k=\pi / 3 \mathrm{cm}^{-1} .$$ Therefore wave speed is $$ v=\omega / k=(40 \pi \mathrm{rad} / \mathrm{s}) /\left(\pi / 3 \mathrm{cm}^{-1}\right)=1.2 \times 10^{2} \mathrm{cm} / \mathrm{s} $$
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