Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 16 - Waves-I - Problems - Page 475: 49b

Answer

$\lambda=60cm$

Work Step by Step

For the pattern shown, the length of the string is equal to 3 half-wavelengths: $L = 3(\frac{λ}{2})$ or $\lambda=\frac{2L}{3}$ $L=90 cm=\frac{90}{100}=0.90m$ putting the value of we get $\lambda=\frac{2(0.90)}{3}$ $\lambda=0.60m$ $\lambda=60cm$
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