Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 11 - Sequences; Induction; the Binomial Theorem - Section 11.3 Geometric Sequences; Geometric Series - 11.3 Assess Your Understanding - Page 844: 9

Answer

See answer below.

Work Step by Step

We need to substitute $1, 2, 3,$ and $4$ for $n$ into the given equation to find the first four terms. $s_1=(3)^1=3$ $s_2=(3)^2=9$ $s_3=(3)^3=27$ $s_4=(3)^4=(3)(3)(3)(3)=81$ We see that the the next term is equal to $3$ times the current term and this implies that the sequence is geometric with a common ratio of $3$.
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