Answer
See answer below.
Work Step by Step
We need to substitute $1, 2, 3,$ and $4$ for $n$ into the given equation to find the first four terms.
$s_1=(3)^1=3$
$s_2=(3)^2=9$
$s_3=(3)^3=27$
$s_4=(3)^4=(3)(3)(3)(3)=81$
We see that the the next term is equal to $3$ times the current term and this implies that the sequence is geometric with a common ratio of $3$.