Answer
The $n^{th}$ term of the sequence is given by the formula:
$a_n =0 \ (\dfrac{1}{2})^{n-1}=0$
and $a_5=0 $
Work Step by Step
We are given: $a_{1}=0 ; \ r=\dfrac{1}{2}$
The $n^{th}$ term of the sequence is given by the formula:
$a_n=a_1r^{n-1}$
$a_n =0 \ (\dfrac{1}{2})^{n-1}=0$
Now, the 5th term can be computed by substituting $5$ for $n$:
$a_5=0 \ (\dfrac{1}{2})^{n-1}=0$