Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 11 - Sequences; Induction; the Binomial Theorem - Section 11.3 Geometric Sequences; Geometric Series - 11.3 Assess Your Understanding - Page 844: 38

Answer

Thus, the general formula for the given sequence is: $a_n=21 (\dfrac{1}{3})^{n-1}$

Work Step by Step

The $n^{th}$ term of a geometric sequence is given by the formula: $ a_n=a_1r^{n-1}$ where $r$=common ratio and $a_1$= the first term The common ratio of a geometric sequence is equal to the quotient (ratio) of any term and the term before it: $ \ r = \dfrac{a_n}{a_{n-1}}$ or, $r=\dfrac{a_2}{a_1}$ Here $a_2=7$ and $r=\dfrac{1}{3}$ So, $a_2=a_1r^{2-1}=7\\a_1\cdot(\dfrac{1}{3})^1=7\\a_1=21$ Thus, the general formula for the given sequence is: $a_n=21 (\dfrac{1}{3})^{n-1}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.