Answer
The $n^{th}$ term of the sequence is given by the formula:
$a_n =6 \ (-2)^{n-1}$
and $a_5=96$
Work Step by Step
We are given: $a_{1}=6 ; \ r=-2$
The $n^{th}$ term of the sequence is given by the formula:
$a_n=a_1r^{n-1}$
$a_n =6 \ (-2)^{n-1}$
Now, the 5th term can be computed by substituting $5$ for $n$:
$a_5=6 \ (-2)^{5-1} \\ =6 \ (-2)^4 \\=96$
