Answer
$a= 0.601\ cm$, $b= 4.787\ cm$, and $A= 7^\circ09'$
Work Step by Step
Given $B=82^\circ51', c=4.825\ cm$, we have $a=c\ cosB=4.825cos(82^\circ51')\approx0.601\ cm$, $b=c\ sinB=4.825sin(82^\circ51')\approx4.787\ cm$, and $A=90^\circ-82^\circ51'=7^\circ09'$
