Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.4 Solutions and Applications off Right Triangles - 5.4 Exercises - Page 547: 19

Answer

$A=47.9108^{\circ}$ $c=84.816\,cm$ $a=62.942\,cm$

Work Step by Step

The sum of angles in a triangle is $180^{\circ}$. $\implies$ Angle $A=180^{\circ}-(90^{\circ}+42.0892^{\circ})=47.9108^{\circ}$ $\sin B=\sin 42.0892^{\circ}=\frac{\text{opposite side}}{\text{hypotenuse}}=\frac{56.851\,cm}{c}$ $\implies c=\frac{56.851\,cm}{\sin42.0892^{\circ}}=84.816\,cm$ $\tan B=\tan 42.0892^{\circ}=\frac{\text{opposite side}}{\text{adjacent side}}=\frac{56.851\,cm}{a}$ $\implies a=\frac{56.851\,cm}{\tan 42.0892^{\circ}}=62.942\,cm$
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