Answer
$a= 306\ m$, $b= 1248\ m$, and $B= 76^\circ13'$
Work Step by Step
Given $A=13^\circ47', c=1285\ m$, we have $a=c\ sinA=1285sin(13^\circ47')\approx306\ m$, $b=c\ cosA=1285cos(13^\circ47')\approx1248\ m$, and $B=90^\circ-13^\circ47'=76^\circ13'$