Answer
$A=63^\circ$, $B=27^\circ$, and $c=1076\ m$
Work Step by Step
Given $a=958\ m, b=489\ m$, we have $tanA=\frac{a}{b}=\frac{958}{489}$, thus $A=atan(\frac{958}{489})\approx 63^\circ$, $B=90^\circ- 63^\circ= 27^\circ$, and $c=\sqrt {a^2+b^2}=\sqrt {958^2+489^2}\approx1076\ m$
