Answer
$A= 51^\circ$, $B= 39^\circ$, and $a= 40\ ft$
Work Step by Step
Given $b=32\ ft, c=51\ ft$, we have $sinB=\frac{b}{c}=\frac{32}{51}$, thus $B=asin(\frac{32}{51})\approx39^\circ$, $A=90^\circ-39^\circ=51^\circ$, and $a=\sqrt {c^2-b^2}=\sqrt {51^2-32^2}\approx40\ ft$
