Answer
$A= 37^\circ40'$, $B= 52^\circ20'$, $c= 20.5\ ft$
Work Step by Step
Use the definitions of tangent, we have $tan(A)=\frac{12.5}{16.2}$ which gives $A=atan(\frac{12.5}{16.2})\approx37^\circ40'$, thus angle $B=90^\circ-37^\circ40'=52^\circ20'$.
Use Pythagorean's Theorem, we have $c=\sqrt {(12.5)^2+(16.2)^2}\approx20.5\ ft$ (or use $c=\frac{12.5}{sinA}$)
