Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.4 Solutions and Applications off Right Triangles - 5.4 Exercises - Page 547: 16

Answer

$Y=42.2^{\circ}$ $x=66.4\,cm$ $y=60.2\,cm$

Work Step by Step

Sum of angles in a triangle is $180^{\circ}$ $\implies$ Angle $Y=180^{\circ}-(90^{\circ}+47.8^{\circ})$ $=42.2^{\circ}$ Now, $\sin 47.8^{\circ}=\frac{\text{side opposite}}{\text{hypotenuse}}=\frac{x}{89.6\,cm}$ Or $x=\sin 47.8^{\circ}\times89.6\,cm=66.4\,cm$ $\cos 47.8^{\circ}=\frac{\text{side adjacent}}{\text{hypotenuse}}=\frac{y}{89.6\,cm}$ $\implies y=\cos 47.8^{\circ}\times89.6\,cm=60.2\,cm$
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