Answer
$B= 29.0^\circ$, $a= 70.7\ cm$, and $c= 80.9\ cm$
Work Step by Step
Given $A=61.0^\circ, b=39.2\ cm$, we have $B=90.0^\circ-61.0^\circ=29.0^\circ$, $a=b\ tanA=39.2tan(61.0^\circ)\approx70.7\ cm$, and $c=\frac{b}{sinB}=\frac{39.2}{sin(29.0^\circ)}\approx80.9\ cm$