Answer
$A= 62^\circ50'$, $B= 27^\circ10'$, and $c= 85.9\ yd$
Work Step by Step
Given $a=76.4\ yd, b=39.3\ yd$, we have $tanA=\frac{a}{b}=\frac{76.4}{39.3}$, thus $A=atan(\frac{76.4}{39.3})\approx 62^\circ50'$, $B=90^\circ- 62^\circ50'= 27^\circ10'$, and $c=\sqrt {a^2+b^2}=\sqrt {76.4^2+39.3^2}\approx85.9\ yd$
