Answer
$A= 38.3^\circ$, $b= 35.6\ ft$, and $c= 45.3\ ft$
Work Step by Step
Given $B=51.7^\circ, a=28.1\ ft$, we have $A=90.0^\circ-51.7^\circ=38.3^\circ$, $b=a\ tanB=28.1tan(51.7^\circ)\approx35.6\ ft$, and $c=\frac{a}{sinA}=\frac{28.1}{sin(38.3^\circ)}\approx45.3\ ft$
