Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Cumulative Review Exercises - Page 1181: 9

Answer

See below:

Work Step by Step

Consider the provided function, $ y=2\sin \left( 2x+\frac{\pi }{2} \right)$ The general sine function equation looks as follows: $ y=A\sin \left( Bx+c \right)$ From both equations above: $ A=2,\text{ }B=2\text{ and c}=\frac{\pi }{2}$ Therefore, amplitude is: $\left| A \right|=\left| 2 \right|=2$ $\begin{align} & \text{Period=}\frac{2\pi }{B} \\ & =\frac{2\pi }{2} \\ & =\pi \end{align}$ If c is a positive real number, the graph of $ f\left( cx \right)$ is the graph of $ y=f\left( x \right)$ stretched horizontally by $ c $ units. If h is a positive real number, the graph of $ hf\left( x \right)$ is the graph of $ y=f\left( x \right)$ stretched vertically by $ h $ units. If c is a positive real number, then the graph of $ f\left( x+c \right)$ is the graph of $ y=f\left( x \right)$ shifted to the left c units. Now, the provided function is: $ y=2\sin \left( 2x+\frac{\pi }{2} \right)$ The graph of above function can be seen as transformations of the parent function $ y=\sin \left( x \right)$, Stretch the graph of $ y=\sin \left( x \right)$ by 2 units horizontally and stretch the graph vertically by 2 units. And also shift the graph to left by $\frac{\pi }{2}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.