Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Cumulative Review Exercises - Page 1181: 19

Answer

The simplest form of the expression ${{\left( {{x}^{2}}-3y \right)}^{4}}$ is ${{x}^{8}}+81{{y}^{4}}+54{{x}^{4}}{{y}^{2}}-12{{x}^{6}}y-108{{x}^{2}}{{y}^{3}}$.

Work Step by Step

Consider the expression ${{\left( {{x}^{2}}-3y \right)}^{4}}$, The above expression can be written as, ${{\left( {{x}^{2}}-3y \right)}^{2}}{{\left( {{x}^{2}}-3y \right)}^{2}}$ Apply the identity ${{\left( a+b \right)}^{2}}={{a}^{2}}+{{b}^{2}}+2ab$, $\begin{align} & {{\left( {{x}^{2}}-3y \right)}^{2}}={{\left( {{x}^{2}} \right)}^{2}}+{{\left( 3y \right)}^{2}}-2\left( {{x}^{2}} \right)\left( 3y \right) \\ & ={{x}^{4}}+9{{y}^{2}}-6{{x}^{2}}y \end{align}$ Substitute the value of ${{\left( {{x}^{2}}-3y \right)}^{2}}$ in ${{\left( {{x}^{2}}-3y \right)}^{2}}{{\left( {{x}^{2}}-3y \right)}^{2}}$ $\begin{align} & {{\left( {{x}^{2}}-3y \right)}^{2}}{{\left( {{x}^{2}}-3y \right)}^{2}}=\left( {{x}^{4}}+9{{y}^{2}}-6{{x}^{2}}y \right)\left( {{x}^{4}}+9{{y}^{2}}-6{{x}^{2}}y \right) \\ & ={{x}^{4}}\left( {{x}^{4}}+9{{y}^{2}}-6{{x}^{2}}y \right)+9{{y}^{2}}\left( {{x}^{4}}+9{{y}^{2}}-6{{x}^{2}}y \right)-6{{x}^{2}}y\left( {{x}^{4}}+9{{y}^{2}}-6{{x}^{2}}y \right) \\ & ={{x}^{8}}+9{{x}^{4}}{{y}^{2}}-6{{x}^{6}}y+9{{x}^{4}}{{y}^{2}}+81{{y}^{4}}-54{{x}^{2}}{{y}^{3}}-6{{x}^{6}}y-54{{x}^{2}}{{y}^{3}}+36{{x}^{4}}{{y}^{2}} \end{align}$ Group together the like terms and solve them, $\begin{align} & {{\left( {{x}^{2}}-3y \right)}^{4}}={{x}^{8}}+9{{x}^{4}}{{y}^{2}}-6{{x}^{6}}y+9{{x}^{4}}{{y}^{2}}+81{{y}^{4}}-54{{x}^{2}}{{y}^{3}}-6{{x}^{6}}y-54{{x}^{2}}{{y}^{3}}+36{{x}^{4}}{{y}^{2}} \\ & ={{x}^{8}}+81{{y}^{4}}+9{{x}^{4}}{{y}^{2}}+9{{x}^{4}}{{y}^{2}}+36{{x}^{4}}{{y}^{2}}-6{{x}^{6}}y-6{{x}^{6}}y-54{{x}^{2}}{{y}^{3}}-54{{x}^{2}}{{y}^{3}} \\ & ={{x}^{8}}+81{{y}^{4}}+54{{x}^{4}}{{y}^{2}}-12{{x}^{6}}y-108{{x}^{2}}{{y}^{3}} \end{align}$ Therefore, the simplest form of the expression ${{\left( {{x}^{2}}-3y \right)}^{4}}$ is ${{x}^{8}}+81{{y}^{4}}+54{{x}^{4}}{{y}^{2}}-12{{x}^{6}}y-108{{x}^{2}}{{y}^{3}}$.
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