Answer
$|A|=4$, $p=2 $, $\phi=-\frac{2}{\pi}$.
See graph.
Work Step by Step
Step 1. Given $y=4sin(\pi x+2)=4sin[\pi (x+\frac{2}{\pi})]$, we can find the amplitude $|A|=4$, period $p=\frac{2\pi}{\pi}=2 $, and phase shift $\phi=-\frac{2}{\pi}$.
Step 2. See graph.
