Answer
See graph.
Work Step by Step
Step 1. Given $y=2tan(4x-\pi)=2tan[4(x-\frac{\pi}{4})]$, we can find the period $p=\frac{\pi}{4}$, and phase shift $\phi=\frac{\pi}{4}$.
Step 2. To plot, start from one branch of $y=tan(x)$, shift $\phi$ to the right, shrink horizontally by a factor of $\frac{1}{4}$, and then stretch vertically by a factor of $2$. See graph.
