Answer
See graph.
Work Step by Step
Step 1. Given $y=\frac{1}{2}cot(2x-\pi)=\frac{1}{2}cot[2(x-\frac{\pi}{2})]$, we can find the period $p=\frac{\pi}{2}$, and phase shift $\phi=\frac{\pi}{2}$.
Step 2. To plot, start from one branch of $y=cot(x)$, shift $\phi$ to the right, shrink horizontally by a factor of $\frac{1}{2}$, then shrink vertically by a factor of $\frac{1}{2}$, and then use the period to repeat the resulting curve. See graph.
