Answer
$|A|=2$, $p= 1 $, $\phi=\frac{2}{\pi}$.
See graph.
Work Step by Step
Step 1. Given $y=2cos(2\pi x-4)-1=2cos[2\pi (x-\frac{2}{\pi})]-1$, we can find the amplitude $|A|=2$, period $p=\frac{2\pi}{2\pi}=1 $, and phase shift $\phi=\frac{2}{\pi}$.
Step 2. See graph.
