Answer
$|A|=2$, $p=\frac{2\pi}{3} $, $\phi=-\frac{\pi}{6}$.
See graph.
Work Step by Step
Step 1. Given $y=2cos(3x+\frac{\pi}{2})=2cos[3(x+\frac{\pi}{6})]$, we can find the amplitude $|A|=2$, period $p=\frac{2\pi}{3} $, and phase shift $\phi=-\frac{\pi}{6}$.
Step 2. See graph.
