Answer
See graph.
Work Step by Step
Step 1. Given $y=\frac{1}{2}sec(3x-\pi)=\frac{1}{2}sec[3(x-\frac{\pi}{3})]$, we can find the period $p=\frac{2\pi}{3}$, and phase shift $\phi=\frac{\pi}{3}$.
Step 2. To plot, start from one period of $y=sec(x)$, shift $\phi$ units to the right, shrink horizontally by a factor of $\frac{1}{3}$, then shrink vertically by a factor of $\frac{1}{2}$, and then use the period to repeat the resulting curve. See graph.
