Answer
$|A|=2$, $p=1 $, $\phi=-\frac{2}{\pi}$.
See graph.
Work Step by Step
Step 1. Given $y=2cos(2\pi x+4)=2cos[2\pi (x+\frac{2}{\pi})]$, we can find the amplitude $|A|=2$, period $p=\frac{2\pi}{2\pi}=1 $, and phase shift $\phi=-\frac{2}{\pi}$.
Step 2. See graph.
