Answer
See graph.
Work Step by Step
Step 1. Given $y=-sec(2\pi x+\pi)=-sec[2\pi(x+\frac{1}{2})]$, we can find the period $p=\frac{2\pi}{2\pi}=1$, and phase shift $\phi=-\frac{1}{2}$.
Step 2. To plot, start from one period of $y=sec(x)$, shift $\frac{1}{2}$ units to the left, shrink horizontally by a factor of $\frac{1}{2\pi}$, then reflect across the x-axis, and then use the period to repeat the resulting curve. See graph.
