Answer
See graph.
Work Step by Step
Step 1. Given $y=-tan(3x+\frac{\pi}{2})=-tan[3(x+\frac{\pi}{6})]$, we can find the period $p=\frac{\pi}{3}$, and phase shift $\phi=-\frac{\pi}{6}$.
Step 2. To plot, start from one period of $y=tan(x)$, shift $\frac{\pi}{6}$ units to the left, shrink horizontally by a factor of $\frac{1}{3}$, then reflect across the x-axis, and then use the period to repeat the resulting curve. See graph.
