Answer
See graph.
Work Step by Step
Step 1. Given $y=-cot(2x+\frac{\pi}{2})=-cot[2(x+\frac{\pi}{4})]$, we can find the period $p=\frac{\pi}{2}$, and phase shift $\phi=-\frac{\pi}{4}$.
Step 2. To plot, start from one period of $y=cot(x)$, shift $\frac{\pi}{4}$ units to the left, shrink horizontally by a factor of $\frac{1}{2}$, then reflect across the x-axis, and then use the period to repeat the resulting curve. See graph.
