Answer
$$\int\frac{e^{\sqrt x}}{\sqrt x}dx=2e^{\sqrt x}+C$$
Work Step by Step
$$A=\int\frac{e^{\sqrt x}}{\sqrt x}dx$$
We set $a=\sqrt x$, which means $$da=\frac{1}{2\sqrt x}dx$$ $$\frac{1}{\sqrt x}dx=2da$$
Therefore, $$A=2\int e^ada$$ $$A=2e^a+C$$ $$A=2e^{\sqrt x}+C$$
