Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.4 - The Fundamental Theorem of Calculus - Exercises 5.4 - Page 287: 41

Answer

$\frac{-sin(x)}{2\sqrt x}$

Work Step by Step

To find the derivative of an integral, plug in the limits as if you had already integrated and are plugging in the limits to evaluate. Apply chain rule to the variable limit if applicable: $=0-sin((\sqrt x)^2)\times\frac{1}{2}(x)^{-1/2}=\frac{-sin(x)}{2\sqrt x}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.