Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.4 - The Fundamental Theorem of Calculus - Exercises 5.4 - Page 287: 33

Answer

$\frac{1}{\pi}(4^\pi-2^\pi)$

Work Step by Step

$\int^{4}_{2}x^{\pi-1}dx$ =$\frac{x^\pi}{\pi}|^4_2$ =$\frac{1}{\pi}(4^\pi-2^\pi)$
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