Answer
$f_x=1/2(x^2+y^2)^{-1/2}\times 2x$
$f_y=1/2(x^2+y^2)^{-1/2}\times 2y$
Work Step by Step
Take the first partial derivatives of the given function. When taking a partial derivative with respect to x, treat y as a constant, and vice versa:
$f_x=1/2(x^2+y^2)^{-1/2}\times 2x$
$f_y=1/2(x^2+y^2)^{-1/2}\times 2y$