Answer
a) 4x and b) -3
Work Step by Step
a) Apply the chain rule as follows:
$\dfrac{∂(2x^2-3y-4) }{∂x}= 4x+0+0=4x$
b) Apply the chain rule as follows:
$\dfrac{∂(2x^2-3y-4) }{∂y}= 0-3+0=-3$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 14: Partial Derivatives - Section 14.3 - Partial Derivatives - Exercises 14.3 - Page 807: 1
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