Answer
$f_x=3(2x-3y)^2\times 2$
$f_y=3(2x-3y)^2\times -3$
Work Step by Step
Take the first partial derivatives of the given function. When taking a partial derivative with respect to x, treat y as a constant, and vice versa:
$f_x=3(2x-3y)^2\times 2$
$f_y=3(2x-3y)^2\times -3$