Answer
$sech^2 (x+2y+3z)$;
$2sech^2 (x+2y+3z)$;
$3 \space sech^2 (x+2y+3z)$
Work Step by Step
We need to take the first partial derivatives of the given function.
In order to find the partial derivative, we will differentiate with respect to $x$, by keeping $y$ and $z$ as a constant, and vice versa:
$f_x=sech^2 (x+2y+3z) \times \dfrac{\partial (x+2y-3z)}{\partial x} =sech^2 (x+2y+3z)$
$f_y=sech^2 (x+2y+3z) \times \dfrac{\partial (x+2y-3z)}{\partial y} =2sech^2 (x+2y+3z)$
$f_z= sech^2 (x+2y+3z) \times \dfrac{\partial (x+2y-3z)}{\partial z} =3 \space sech^2 (x+2y+3z)$
