Answer
$f_x=e^{-x}cos(x+y)-e^{-x}sin(x+y)$
$f_y=e^{-x}cos(x+y)$
Work Step by Step
Take the first partial derivatives of the given function. When taking a partial derivative with respect to x, treat y as a constant, and vice versa:
$f_x=e^{-x}cos(x+y)-e^{-x}sin(x+y)$
$f_y=e^{-x}cos(x+y)\times1$