Answer
$f_x=\frac{1}{x+y}$
$f_y=\frac{1}{x+y}$
Work Step by Step
Take the first partial derivatives of the given function. When taking a partial derivative with respect to x, treat y as a constant, and vice versa:
$f_x=\frac{1}{x+y}\times1$
$f_y=\frac{1}{x+y}\times1$